But there can be derived even more. To this purpose, we will place two charges at any two positions on such an orbit, send them on their way and select the same sign for both. If we send them exactly in the opposite direction an impact or a mutual penetration after a short period of time (as we know too little about the charges themselves) would be unavoidable. However, in this thought experiment the stability conditions are not met; so we reject this solution as being not stable.
Next we will send the two charges on their way again, select the same sign again, but now the same direction for the two partners. After a short time they will face each other in equivalent parts of the orbit due to the Coulomb forces of external interaction; apparently we would have a minimum of temporal change of the external interaction. However, unfortunately this is not the case because we do not see any reason why these two charges should stick together at all. Thus, we reject this solution as well and formulate (what we know well already ): there is no elementary particle that is doubly- or multiply-charged.
Now we begin our speculation anew. This time we place two charges with opposite sign and opposite orientation into our orbit. This solution is apparently unstable either because it does not satisfy the stability theorem.
Finally, we inquire about the behavior of two charges with opposite sign that we send into the orbit with the same orientation. If they start such that their secant intersecting the two charges will not intersect the center of the sphere, in other words, the two charges do not always face each other diametrically, they will continuously approach each other and the stability theorem again will not be satisfied. But if we allow the two charges to be exactly opposite each other at every point of the orbit, they will start “hunting” each other without ever reaching each other. Thus, one could assume that such a model that meets the stability theorem represents a neutral elementary particle. (By the way, this model is very similar to our completely occupied spherical orbits in the electron shell .) But it can easily be seen that such a model cannot be stable at all because the two charges, as far as they only slightly deviate from the diametrical constellation, must immediately approach each other, which comes down to the case discussed above.