We summarize: an uncharged π-meson should be extremely instable and in fact: the uncharged π-meson has the shortest decay time of all instable elementary particles.
Consequently, there must be something right in the stability theorem because it provides quite reasonable conclusions.
Now we ask: possibly we may place even more charges on the orbit of the Tu model (π-meson)? First we will add only one charge to the pair. This procedure must fail immediately because the already labile oscillation now becomes completely instable. But maybe we can add another “pair” to the already existing one because we have four different directions of self-interaction. Perhaps via an appropriate arrangement it will be possible for the charges not to influence each other in their self-interaction! For this purpose look at Fig. 43:
The constellation 1=e⁺, 2=e⁺, 3=e^-, 4=e^- is out of question since now the charges are distributed such that the secant connecting two different charges is not even approximately constant over time. Therefore we reject this solution because it does not satisfy the stability theorem. For similar reasons we also have to reject the solution 1=e⁺, 2=e^-, 3=e⁺, 4=e^- because always two identically charged electrons sometimes get in close vicinity in closely adjacent orbit segments and also remove from each other again. For these reasons we can state that an uncharged π-meson, which decomposes into four simple charges during decay, may not exist; this is confirmed by experience.

Now, we come to the next model, the escribed octahedron. It is certain that an uncharged sister particle exists here as well, if one pair ( e⁺ und e^- ) of charges occupies the orbit diametrically in the same sense of revolution. According to the same arguments as discussed before with the Tu model, the external interaction of the magnetic energy is equal to zero and the electrical portion of the external interaction is also an (instable) minimum.